-0.25x^2+70x-1225=0

Solution for -0.25x^2+70x-1225=0 equation:

-0.25x^2+70x-1225=0

a = -0.25; b = 70; c = -1225;
Δ = b2-4ac
Δ = 702-4·(-0.25)·(-1225)
Δ = 3675
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3675}=\sqrt{1225*3}=\sqrt{1225}*\sqrt{3}=35\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-35\sqrt{3}}{2*-0.25}=\frac{-70-35\sqrt{3}}{-0.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+35\sqrt{3}}{2*-0.25}=\frac{-70+35\sqrt{3}}{-0.5}
$